741 Posts

Under certain circumstances, attacks may deal 0 damage to an enemy.

If one MG is consistently dealing 0 damage to another MG (due to the great difference between the attackers attack and the defender's defense), the damage will always be 0, even if it is a critical hit.

I propose the critical hit formula be tweaked *slightly* to this:

"a" the damage of the normal attack
"f" is the function which alters the damage dealt on a critical hit
"p" is my proposed function, tweaking things slightly
"n" is a generic value or constant (unimportant)

Currently:
Critical Hit = f(a)

I propose:
Critical Hit = p(f(a))

Where...
p = (n) + 1


In other (probably simpler) words, whatever the final result of the critical hit, you add 1 damage to that total. This way, should the critical hit result in 0 damage, it instead deals 1 damage.



Additional References:
http://forum.djartsgames.ca/?thread_id=1727
http://www.youtube.com/watch?v=DrZNpI_yOrc
:P

407 Posts

All that Nate suggested is that a 0 damage critical hit should do 1 damage instead, Jonathan. I don't know what the intention behind this is, but there would certainly not be a problem with it.

741 Posts

No worries. It's not a big difference. It just struck me as very odd that a "critical" hit could do 0 damage.